查看原文
其他

HiveSQL高级进阶技巧

花荣 BAT大数据架构 2022-11-29

直接上干货,HiveSQL高级进阶技巧,重要性不言而喻。掌握这10个技巧,你的SQL水平将有一个质的提升!


1.删除:

insert overwrite tmp select * from tmp where id != '666';


2.更新:

insert overwrite tmp select id,label, if(id = '1' and label = 'grade','25',value) as value from tmp where id != '666';


3.行转列:

-- Step03:最后将info的内容切分select id,split(info,':')[0] as label,split(info,':')[1] as valuefrom (-- Step01:先将数据拼接成“heit:180,weit:60,age:26”    select id,concat('heit',':',height,',','weit',':',weight,',','age',':',age) as value     from tmp) as tmp-- Step02:然后在借用explode函数将数据膨胀至多行lateral view explode(split(value,',')) mytable as info;


4.列转行1:

select tmp1.id as id,tmp1.value as height,tmp2.value as weight,tmp3.value as age from (select id,label,value from tmp2 where label = 'heit') as tmp1joinon tmp1.id = tmp2.id(select id,label,value from tmp2 where label = 'weit') as tmp2joinon tmp1.id = tmp2.id(select id,label,value from tmp2 where label = 'age') as tmp3on tmp1.id = tmp3.id;


5.列转行2:

selectid,tmpmap['height'] as height,tmpmap['weight'] as weight,tmpmap['age'] as agefrom (    select id,    str_to_map(concat_ws(',',collect_set(concat(label,':',value))),',',':') as tmpmap   from tmp2 group by id) as tmp1;


6.分析函数1:

select id,label,value,       lead(value,1,0)over(partition by id order by label) as lead,       lag(value,1,999)over(partition by id order by label) as lag, first_value(value)over(partition by id order by label) as first_value, last_value(value)over(partition by id order by label) as last_valuefrom tmp;


7.分析函数2:

select id,label,value, row_number()over(partition by id order by value) as row_number, rank()over(partition by id order by value) as rank, dense_rank()over(partition by id order by value) as dense_rankfrom tmp;


8.多维分析1:

select col1,col2,col3,count(1), Grouping__ID from tmp group by col1,col2,col3grouping sets(col1,col2,col3,(col1,col2),(col1,col3),(col2,col3),())


9.多维分析2:

select col1,col2,col3,count(1),       Grouping__ID from tmp group by col1,col2,col3with cube;


10.数据倾斜groupby:

select label,sum(cnt) as all from ( select rd,label,sum(1) as cnt from ( select id,round(rand(),2) as rd,value from tmp1    ) as tmp group by rd,label) as tmpgroup by label;


11.数据倾斜join:

select label,sum(value) as all from ( select rd,label,sum(value) as cnt from ( select tmp1.rd as rd,tmp1.label as label,tmp1.value*tmp2.value as value from ( select id,round(rand(),1) as rd,label,value from tmp1 ) as tmp1 join ( select id,rd,label,value from tmp2 lateral view explode(split('0.0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9',',')) mytable as rd ) as tmp2 on tmp1.rd = tmp2.rd and tmp1.label = tmp2.label ) as tmp1 group by rd,label) as tmp1group by label;


有疑惑加我微信一起讨论:bat6188


您可能也对以下帖子感兴趣

文章有问题?点此查看未经处理的缓存